In Exercises 1 to 4, verify the divergence theorem for the given region \(W\), boundary \(\partial\! W\) oriented outward, and vector field \(\textbf{F}\).
\( W = [0,1] \times [0,1] \times [0,1] \textbf{F} = x \textbf{i} + y \textbf{j} + z \textbf{k}\)
\(W\) as in Exercise 1, and \(\textbf{F} = zy \textbf{i} + xz \textbf{j} + xy \textbf{k}\)
\( W = \{ (x,y,z) : x^2 + y^2 + z^2 \leq 1 \}\) \quad (the unit ball), \(\textbf{F} = x \textbf{i} + y \textbf{j} + z \textbf{k}\)
\(W\) as in Exercise 3, and \(\textbf{F} = -y \textbf{i} + x \textbf{j} + z \textbf{k}\)
Use the divergence theorem to calculate the flux of \({\bf F} = (x-y) {\bf i} + (y -z) {\bf j} + (z-x){\bf k}\) out of the unit sphere.
Let \({\bf F}=x^3{\bf i}+y^3{\bf j}+z^3{\bf k}\). Evaluate the surface integral of \({\bf F}\) over the unit sphere.
Evaluate \({\intop\!\!\!\intop}_{\partial\! W}{\bf F}\,{\cdot}\,{\,d} {\bf S}\), where \({\bf F}=x{\bf i}+y{\bf j}+z{\bf k}\) and \(W\) is the unit cube (in the first octant). Perform the calculation directly and check by using the divergence theorem.
Repeat Exercise 7 for
Let \({\bf F}=y{\bf i} +z{\bf j} +xz{\bf k}\). Evaluate \({\intop\!\!\!\intop}_{\partial\! W}{\bf F}\,{\cdot}\,{\,d} {\bf S}\) for each of the following regions \(W\):
Repeat Exercise 9 for \({\bf F}=(x-y){\bf i}+(y-z){\bf j}+ (z-x){\bf k}\). [The solution to part (b) only is in the Study Guide to this text.]
Find the flux of the vector field \({\bf F}= (x-y^2){\bf i} + y{\bf j} + x^3 {\bf k}\) out of the rectangular solid \([0,1] \times [1,2] \times [1,4]\).
Evaluate \({\intop\!\!\!\intop}_S{\bf F}\,{\cdot}\,{\,d} {\bf S}\), where \({\bf F}=3xy^2{\bf i}+3x^2y{\bf j}+z^3{\bf k}\) and \(S\) is the surface of the unit sphere.
Let \(W\) be the pyramid with top vertex \((0,0,1)\), and base vertices at \((0,0,0)\), \((1,0,0)\), \((0,1,0)\), and \((1,1,0)\). Let \(S\) be the two-dimensional closed surface bounding \(W\), oriented outward from \(W\). Use Gauss’ theorem to calculate \({\intop\!\!\!\intop}_{S} \textbf{F} \cdot d \textbf{S}\), where: \[ \textbf{F}(x,y,z) = (x^2 y, 3y^2 z, 9z^2 x). \]
Let \(W\) be the three-dimensional solid enclosed by the surfaces \(x = y^2\), \(x=9\), \(z=0\), and \(x=z\). Let \(S\) be the boundary of \(W\). Use Gauss’ theorem to find the flux of \(\textbf{F}(x,y,z) = (3x - 5y)i + (4z - 2y)j + (8yz)k\) across \(S\): \({\intop\!\!\!\intop}_{S} \textbf{F} \cdot d \textbf{S}\).
Evaluate \({\intop\!\!\!\intop}_{\partial\! W} {\bf F} {\,{\cdot}\,} {\bf n} {\,d} A\), where \({\bf F}(x,y,z) = x{\bf i} + y{\bf j} - z{\bf k}\) and \(W\) is the unit cube in the first octant. Perform the calculation directly and check by using the divergence theorem.
Evaluate the surface integral \({\intop\!\!\!\intop}_{\partial S} {\bf F} {\,{\cdot}\,} {\bf n} {\,d} A\), where \({\bf F}(x,y,z) = {\bf i} + {\bf j} + z(x^2 + y^2)^2{\bf k}\) and \(\partial\! S\) is the surface of the cylinder \(x^2 + y^2 \le 1, 0\le z \le 1\).
Prove that \begin{eqnarray*} \intop\!\!\!\intop\!\!\!\intop\nolimits_{W} ({\nabla}\!f) \,{\cdot}\, {\bf F} {\it {\,d} x}\, {\it dy} {\,d} z &=& \intop\!\!\!\intop\nolimits_{\partial\! W} f{\bf F} {\,{\cdot}\,} {\bf n} {\,d} S\\[6pt] &&-\ \intop\!\!\!\intop\!\!\!\intop\nolimits_{W} f{\nabla} {\,{\cdot}\,} {\bf F} {\it {\,d} x}\, {\it dy}\, {\,d} z. \end{eqnarray*}
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Prove the identity \[ {\nabla}{\,{\cdot}\,} ({\bf F} \times {\bf G}) = {\bf G}{\,{\cdot}\,} ({\nabla}\times {\bf F}) - {\bf F} {\,{\cdot}\,} ({\nabla}\times {\bf G}). \]
Show that \({\intop\!\!\!\intop\!\!\!\intop}_{W}(1/r^2)\, {\it {\,d} x}\,{\it dy}\,{\,d} z = {\intop\!\!\!\intop}_{\partial\! W}({\bf r}{\,{\cdot}\,} {\bf n}/r^2){\,d} S\), where \({\bf r} = x{\bf i} + y{\bf j} + z{\bf k}\).
Fix vectors \({\bf v}_1,\ldots, {\bf v}_k \in {\mathbb R}^3\) and numbers (“charges”) \(q_1,\ldots, q_k\). Define the function \(\phi\) by \(\phi(x,y,z) = \sum_{i=1}^k q_i/(4\pi \|{\bf r} - {\bf v}_i\|)\), where \({\bf r} =(x,y,z)\). Show that for a closed surface \(S\) and \({\bf E} = - {\nabla}\phi\), \[ \intop\!\!\!\intop\nolimits_{S}{\bf E}{\,{\cdot}\,} {\,d}{\bf S}= Q, \] where \(Q\) is the total charge inside \(S\). (Assume that Gauss’ law from Theorem 10 applies and that none of the charges are on \(S\).)
Prove Green’s identities \[ \intop\!\!\!\intop\nolimits_{\partial\! W} f{\nabla}g {\,{\cdot}\,} {\bf n}{\,d} S = \intop\!\!\!\intop\!\!\!\intop\nolimits_{W}(f\nabla^2 g + {\nabla}\!f{\,{\cdot}\,} {\nabla}g) {\,d} V \] and \[ \intop\!\!\!\intop\nolimits_{\partial\! W} (f{\nabla}g - g{\nabla} f) {\,{\cdot}\,} {\bf n} {\,d} S = \intop\!\!\!\intop\!\!\!\intop\nolimits_{W} (f \nabla^2 g - g\nabla^2\! f) {\,d} V. \]
Suppose \({\bf F}\) satisfies div \({\bf F}=0\) and curl \({\bf F} = {\bf 0}\) on all of \({\mathbb R}^3\). Show that we can write \({\bf F} = {\nabla}\! f\), where \(\nabla^2 f = 0\).
Let \(\rho\) be a continuous function on \({\mathbb R}^3\) such that \(\rho({\bf q})=0\) except for \({\bf q}\) in some region \(W\). Let \({\bf q}\in W\) be denoted by \({\bf q} = (x,y,z)\). The potential of \(\rho\) is defined to be the function \[ \phi({\bf p}) = \intop\!\!\!\intop\!\!\!\intop\nolimits_{W} \frac{\rho({\bf q})}{4\pi\|{\bf p}-{\bf q}\|} {\,d} V({\bf q}), \] where \(\|{\bf p}-{\bf q}\|\) is the distance between \({\bf p}\) and \({\bf q}\).
[HINT: Use part (a).] (Notice that if \(\rho\) is a charge density, then the integral defining \(\phi\) may be thought of as the sum of the potential at \({\bf p}\) caused by point charges distributed over \(W\) according to the density \(\rho\).)
Suppose \({\bf F}\) is tangent to the closed surface \(S= \partial\! W\) of a region \(W\). Prove that \[ \intop\!\!\!\intop\!\!\!\intop\nolimits_{W} ({\hbox{div }} {\bf F}){\,d} V= 0. \]
Use Gauss’ law and symmetry to prove that the electric field due to a charge \(Q\) evenly spread over the surface of a sphere is the same outside the surface as the field from a point charge \(Q\) located at the center of the sphere. What is the field inside the sphere?
Reformulate Exercise 25 in terms of gravitational fields.
Show how Gauss’ law can be used to solve part (b) of Exercise 29 in Section 8.4.
Let \(S\) be a closed surface. Use Gauss’ theorem to show that if \({\bf F}\) is a \(C^2\) vector field, then we have \({\intop\!\!\!\intop}_s({\nabla} \times {\bf F})\, {\cdot}\, d{\bf S} =0\).
Let \(S\) be the surface of region \(W\). Show that \[ \intop\!\!\!\intop\nolimits_S {\bf r}\,{\cdot}\, {\bf n}\, dS =3 \hbox{ volume } (W). \]
Explain this geometrically.
For a steady-state charge distribution and divergence-free current distribution, the electric and magnetic fields \({\bf E}(x,y,z)\) and \({\bf H}(x,y,z)\) satisfy \begin{eqnarray*} &&{\nabla}\times{\bf E}= {\bf 0},\qquad {\nabla}\,{\cdot}\, {\bf H}=0,\qquad {\nabla}\,{\cdot}\,{\bf J}=0, \qquad {\nabla}\,{\cdot}\, {\bf E}=\rho,\\ &&\qquad\hbox{and}\qquad {\nabla}\times {\bf H}={\bf J}. \end{eqnarray*}
Here \(\rho=\rho(x,y,z)\) and \({\bf J}(x,y,z)\) are assumed to be known. The radiation that the fields produce through a surface \(S\) is determined by a radiation flux density vector field, called the Poynting vector field, \[ {\bf P}={\bf E}\times{\bf H}. \]